q=%26%2340%E7%BE%8E%26%2341%E5%BC%97%E6%B4%9B%E4%BC%8A%E5%BE%B7%26%2340Thomas%2BL.Floyd%26%2341&searchType=standard&isFacet=true&view=standard&searchWay=author&rows=10&sortWay=score&sortOrder=desc&searchWay0=marc&logical0=AND
rows=10&searchWay0=marc&logical0=AND
(美)弗洛伊德(Thomas+L.Floyd)